Casing Design - cont’d
Casing Threads
Using the Halliburton Cementing Tables
Yield Strength of Casing (in tension)
Burst Strength
Effect of Axial Tension on Collapse Strength
Effect of Pipe Bending
Effect of Hydrogen Sulfide
Selection of Casing Settling Depths
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Well Drilling Engineering
More Casing Design
Dr. DO QUANG KHANH
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Casing Design - cont’d
Casing Threads
Using the Halliburton Cementing Tables
Yield Strength of Casing (in tension)
Burst Strength
Effect of Axial Tension on Collapse Strength
Effect of Pipe Bending
Effect of Hydrogen Sulfide
Selection of Casing Settling Depths
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Read: Applied Drilling Engineering, Ch.7
HW #
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Rounded Threads
* 8 per inch
~ Square Threads
* Longer
* Stronger
Integral Joint
* Smaller ID, OD
* Costs more
* Strong
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Tensile force balance on pipe body
Example 7.1:
Compute the body-yield strength for 20-in ., K-55 casing with a nominal wall thickness of 0.635 in . and a nominal weight per foot of 133 lbf/ft .
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Pipe Body Yield Strength
where
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Pipe Body Yield Strength
Example
What is yield strength of body of 7” , 26 #/ft , P-110 casing?
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Internal Yield Pressure for Pipe (Burst)
where
F P = DLP
F T = 2tLY P
DLP = 2tLY P
F P
F T
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Example
For 7” , 26 #/ft P-110 pipe
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Ellipse of
Plasticity
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TENSION
COLLAPSE
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D L = (R + r) Dq - R Dq
Dq
R + r
R
Length of arc, L = R Dq rad
(7.14a)
L
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Figure 7.14 - Incremental stress caused by bending of casing in a directional well
The area of steel, A s , can be expressed conveniently as the weight per foot of pipe divided by the density of steel. For common field units, Eq. 7.14a becomes
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Example
F ab = 64 * 5 * 7 * 35 = 74,400 lbf
F ab = 74,400 lbf
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R c = 22
( R c = 22 corresponds to a yield strength of about 90,000 psi )
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Production casing design load for burst.
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Production casing design load for collapse.
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Tensile Strength of Casing
What is the maximum length of N-80 casing that can hang in an air-filled wellbore
without exceeding the minimum yield strength of the pipe?
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Tensile Strength of Casing
What is the maximum length of N-80 casing that can hang in an air-filled wellbore without exceeding the minimum yield strength of the pipe?
F
W
F MAX = 80,000 A s = A s L MAX 490/144
L MAX = 80,000 * 144/490
L MAX = 23,510 ft
{ With a 1.8 design factor, L MAX = 13,060 ft }
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